>PARAM @ Рост = 1580 @ обхват груди = 920 @ обхват под грудью = 810 @ обхват талии = 790 @ длина спины = 385 <К1/2> @ КОЭФ-Т 1/2 = 0.5 <К1/4> @ КОЭФ-Т 1/4 = 0.25 <К1/8> @ КОЭФ-Т 1/8 = 0.125 <К1/10> @ КОЭФ-Т 1/10 = 0.1 <К1/20> @ КОЭФ-Т 1/20 = 0.05 @ обхват бедер = 970 @ ширина чашечки = 180 >MAIN .Sy. = 0,0 |s|@.Sy.=+<К1/20>*+20,-180 |sv|@.s.=20,90 |P|@.Sy.=<К1/10>*+<К1/20>*+10,-90 |T|@.Sy.=+,-90 |B|@.Sy.=|Sy_T|+<К1/8>*+,-90 |D|@.Sy.=+<К1/2>*+-120,-90 |By|@.B.=30,-180 .Py.\|Sy_By|,.P.+0 .Ty.\|Sy_By|,.T.+0 .Dy.\|Sy_By|,.D.+0 |Pc|@.Py.=2*+<К1/10>*-20,-180 |Pl|@.Pc.=+<К1/10>*++10,-180 |Px|@.Pl.=2*<К1/10>*++10,-180 |Tx|@.Px.=<|P_T|>,<|P_T|> |Ax|@.Tx.=|Sy_T|+<К1/20>*+,90 |X|@.Px.=+<К1/10>*+-5,0 |Sv|@.Ax.=<|s_Sy|>,<|s_Sy|> |Sx|@.Ax.=|Sy_s|+10,-90 .Al.\|Ax_Sv|,.Pl. |A1|@.Al.=60,-90 |Sv_A1| .ac.\|Sy_s|,.Pc. |a|@.ac.=10,-90 |1|@.sv.=5,-90 |1_a| .c.@|Pc_a|=|Pc_a|/4 .Tc.\|T_Tx|,.Pc.+90 |Bx|@.Tx.=<|T_B|>,<|T_B|> |13| @ |Dy_By| = 50,90 |Dy_13| .Dc.#|Pc_Tc|,|Dy_13| .Bc.\|Tc_Dc|,.By.+0 |14| @ |Dc_Bc| = 50,90 |Dc_14| .Tl.#|T_Tc|,|Al_Pl| |T0|@.Tl.=+<К1/4>*-10,-180 |Tx_T0| |15|@.T0.=+<К1/2>*,0 |15_Ty| |16|@.Bx.=+<К1/2>*+,0 |B_16| |X1|@.X.=+<К1/10>*+-20,-180 |X2|@.X.=+<К1/10>*+-10,0 |X3|@.Px.=+<К1/10>*+-10,-90 .p1.\|Sy_P|,.X3. .X4.\|X3_p1|,.X.+90 |17|@.X3.=+<К1/2>*,0 .p2.\|Sy_By|,.p1.+0 |17_p2| .X7.#.X.+ |X_X2|,.X2.+10,$ .X8.#.X.+ |X_X2|,.X7.++<К1/20>*+-5 .X9.#.X.+ |X_X1|,.X1.++<К1/20>*+-15,$ (X7_X8_X4) (X1_X9_X4) .A2.@|Sv_A1|=50 .a2.@|1_a|=40 |P3|@.Py.=40,-180 .P5.@|Py_p2|=|Py_p2|/2 .Dx.#|Tx_Bx|,|D_Dy| .B1.@|Dx_Bx|=|Dx_Bx|/2 ~a2_P3~=3 (P3_P5)=5 .Bl.#|Pl_Tl|,|B_By| .Tv.#|X_X4|,|Tx_Tl| .Bv.\|Bx_Bl|,.Tv. .19.@|Dc_Dy|=10 .20.@|Dc_14|=10 .Dl.#|Tl_Bl|,|Dc_14| .21.@|Dl_Dc|=10 .22.@|Dl_Dx|=10 |23|@.By.=10,0 .25.@|a2_a|=30 ~Dy_19~=1 |26|@.Tv.=|Ty_15|/6,0 |27|@.Tv.=|Ty_15|/6,-180 ~X4_27_Bv~ ~X4_26_Bv~ .28.@|B1_Dl|=|B1_Dl|/3 .29.@|B1_28|=|B1_28|/2 |30| @ |29_28| = 2,90 .31.@|28_Dl|=|28_Dl|/2 |32| @ |31_Dl| = 8,-90 ~B1_30_28_32_22~ |33| @ |X1_X9| = |X1_Px|,-90 |X1_33_X3_Tx_Bx_B1| |34|@.Bl.=|B_16|/4,0 |35|@.Bl.=|B_16|/4,-180 |36|@.Bc.=|B_16|/4,0 |37|@.Bc.=|B_16|/4,-180 |38|@.Tl.=|Ty_15|/6,0 |39|@.Tl.=|Ty_15|/6,-180 |41|@.Tc.=|Ty_15|/6,0 |42|@.Tc.=|Ty_15|/6,-180 .cy.\|Sy_23|,.c.+0 .L.\|Pl_Tl|,.c.+0 .Lx.\|Ax_Bx|,.L.+0 ~21_20~=1,$ ~L_39_34_22~ ~L_38_35_21~ ~c_41_37_19~ ~c_42_36_20~ .46.#|P5_X8|,~c_19~ .48.#~L_22~,|X2_Pl| .49.@|a2_P3|=|a2_P3| / 2 |50|@.49.=<|a2_25|>,<|a2_25|> ~25_50~=0 (46_50)=20 ~X7_48~=2 .51.#|X2_Pl|,~L_21~ .52.#|P5_X8|,~c_20~ ~51_52~=15 ~cy_Py_P5_p2_Ty_23_Dy~ |A2_X4| .Xa. = 100,0 |Xb|@.Xa.=+,0 .Xx.@|Xa_Xb|=|Xa_Xb| / 2 (Xa_Xb)=|Xx_Xb| - (((|Xx_Xb|) * (|Xx_Xb|)) - (|Xa_Xb| * |Xa_Xb|) / 4)^0.5 (Xb_Xa)=|Xx_Xb| - (((|Xx_Xb|) * (|Xx_Xb|)) - (|Xb_Xa| * |Xb_Xa|) / 4)^0.5,$ |47|@.Xx.=+,90 .Xd.#|Xx_47|,(Xa_Xb) .Xc.#|47_Xx|,(Xa_Xb) .X4a.#.Xc.+ 10,.Xx.+|Xx_Xb| .X4aa.#.Xc.+ 10,.Xx.+|Xx_Xb|,$ ~Xx_X4a~=3 ~Xx_X4aa~=3,$ >PIECE .ADD = Dy~23~Ty~p2~P5~P3~a2_25~50~46~41~37~19~Dy >PIECE .ADD = 20~36~42~52~51~38~35~21~20 >PIECE .ADD = 22~34~39~48~X7~X8~X4~X9~X1~33_X3_Tx_Bx_B1~22 .ADD = X4~27~Bv~26~X4 .ADD = A2~X4 >END